Okay, I know this is a simple question. I know I suck at math. I am trying to get to a final dimension of a fired piece of clay of 12" X 4". I did a test firing of a piece of wet clay that was 12.5" x 6" initially, the actual size after clay was fired came out to be 10.75" x 5.25". What size do I need to cut my wet clay to in order to arrive at 12 x 4 after shrinkage? Please show your work or provide a link so I can do this again in the futurre for different sizes. Anyone?
13.95" x 4.57" if it shrinks in the same way as the last test piece. 13.83" x 4.61" if you average out the shrinkage between the two dimensions. 10.75 / 12.5 = 86% of original size 5.25 / 6 = 87.5 % of original size 12 / 0.86 = 13.95 4 / 0.875 = 4.57 The remaining portion of the solution is left as an exercise for the reader.
